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4x^2-130=6x
We move all terms to the left:
4x^2-130-(6x)=0
a = 4; b = -6; c = -130;
Δ = b2-4ac
Δ = -62-4·4·(-130)
Δ = 2116
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2116}=46$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-46}{2*4}=\frac{-40}{8} =-5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+46}{2*4}=\frac{52}{8} =6+1/2 $
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